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Stop `fig run` starting everything when a service has no links

This was thanks to the semantics of project.up(), which starts everything
if you pass it an empty list of service names. (That logic should
probably be moved out to main.py.)

Signed-off-by: Aanand Prasad <[email protected]>
Aanand Prasad пре 11 година
родитељ
комит
944e15fa65
2 измењених фајлова са 14 додато и 7 уклоњено
  1. 8 5
      fig/cli/main.py
  2. 6 2
      tests/integration/cli_test.py

+ 8 - 5
fig/cli/main.py

@@ -220,11 +220,14 @@ class TopLevelCommand(Command):
         service = self.project.get_service(options['SERVICE'])
 
         if not options['--no-deps']:
-            self.project.up(
-                service_names=service.get_linked_names(),
-                start_links=True,
-                recreate=False
-            )
+            deps = service.get_linked_names()
+
+            if len(deps) > 0:
+                self.project.up(
+                    service_names=deps,
+                    start_links=True,
+                    recreate=False,
+                )
 
         tty = True
         if options['-d'] or options['-T'] or not sys.stdin.isatty():

+ 6 - 2
tests/integration/cli_test.py

@@ -103,9 +103,13 @@ class CLITestCase(DockerClientTestCase):
 
 
     @patch('dockerpty.start')
-    def test_run_with_links(self, mock_stdout):
-        mock_stdout.fileno = lambda: 1
+    def test_run_service_without_links(self, mock_stdout):
+        self.command.base_dir = 'tests/fixtures/links-figfile'
+        self.command.dispatch(['run', 'console', '/bin/true'], None)
+        self.assertEqual(len(self.command.project.containers()), 0)
 
+    @patch('dockerpty.start')
+    def test_run_service_with_links(self, mock_stdout):
         self.command.base_dir = 'tests/fixtures/links-figfile'
         self.command.dispatch(['run', 'web', '/bin/true'], None)
         db = self.command.project.get_service('db')