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+# Hot Banana
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+#
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+# I heard that bananas are radioactive. If they are radioactive, then they
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+# radiate energy. How many bananas would you need to power a house?
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+#
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+# https://what-if.xkcd.com/158/
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+
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+# Bananas contain Potassium-40 with the following properties:
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+
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+let molar_mass_40K: MolarMass = 40 g / mol
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+let halflife_40K: Time = 1.25 billion years
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+
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+# 40-K has a natural occcurence of
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+
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+let occurence_40K = 0.0117 percent
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+
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+# We can now compute the radioactivity of natural potassium
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+
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+let decay_rate_40K: Activity = ln(2) / halflife_40K
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+let radioactivity_potassium: Activity / Mass = N_A * occurence_40K * decay_rate_40K / molar_mass_40K -> Bq / g
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+
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+print(radioactivity_potassium)
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+
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+# Next, we come to bananas
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+
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+@aliases(bananas)
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+unit banana
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+
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+# https://fdc.nal.usda.gov/fdc-app.html#/food-details/173944/nutrients
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+
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+let potassium_per_banana = 451 mg / banana
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+
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+let radioactivity_banana: Activity / Banana = potassium_per_banana * radioactivity_potassium -> Bq / banana
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+print(radioactivity_banana)
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+
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+# A single 40-K decay releases an energy of
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+# (https://commons.wikimedia.org/wiki/File:Potassium-40-decay-scheme.svg)
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+
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+let energy_per_decay: Energy = 11 percent * 1.5 MeV + 89 percent * 1.3 MeV
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+
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+# Finally: how many bananas do we need to power a single household?
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+
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+let power_per_banana: Power / Banana = radioactivity_banana * energy_per_decay -> pW / banana
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+print(power_per_banana)
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+
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+unit household
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+let power_consumption_household: Power / Household = 3000 kWh per household per year
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+
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+let bananas_per_household = power_consumption_household / power_per_banana -> bananas / household
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+print(bananas_per_household)
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+
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+# TODO: https://what-if.xkcd.com/158/ says this number should be around 300
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+# quadrillion, but we only get 0.1 quadrillion. 300 quadrillion times "a couple
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+# of picowatt" would be an average power consumption of at least 300 kW /
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+# household, which seems … excessive.
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